经典初级面试题:写出sql查询上一篇和下一篇文章的标题和链接。
获取当前浏览文章id
$id = isset($_GET['id']) > 0 ? intval($_GET['id']) : "";
下一篇文章
$query = mysql_query("SELECT id,title FROM article WHERE id>'$id' ORDER BY id ASC LIMIT 1");
$next = mysql_fetch_array($query);
上一篇文章
$query = mysql_query("SELECT id,title FROM article WHERE id <'$id' ORDER BY id DESC LIMIT 1");
$prev = mysql_fetch_array($query);
<div class="page_nav clearfix">
<div title="下一篇" class="next_page">
<a href="?id=<?php echo $next['id']; ?>"><?php echo $next['title']; ?></a>
</div>
<div title="上一篇" class="pre_page">
<a href="?id=<?php echo $prev['id']; ?>"><?php echo $prev['title']; ?></a>
</div>
</div>
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