jquery实现密码强度的智能判断特效是一款非常实用的jquery特效,基本上每个有会员模块的网站都可用上,可以提示会员注册时输入的密码强度,主要用到了keyup事件。。。
首先引用文件
<link href="Css/xiniu.css" rel="stylesheet" type="text/css">
<script src="jquery.min.js" type="text/javascript"></script>
核心jquery代码如下:
function Tough() {
$('#pwdLevel_1').attr('class', 'ywz_zhuce_hongxian');
$('#pwdLevel_2').attr('class', 'ywz_zhuce_hongxian2');
$('#pwdLevel_3').attr('class', 'ywz_zhuce_hongxian3');
}
function checkPassword(pwdinput) {
var maths, smalls, bigs, corps, cat, num;
var str = $(pwdinput).val()
var len = str.length;
var cat = /.{16}/g
if (len == 0) return 1;
if (len > 16) { $(pwdinput).val(str.match(cat)[0]); }
cat = /.*[\u4e00-\u9fa5]+.*$/
if (cat.test(str)) {
return -1;
}
cat = /\d/;
var maths = cat.test(str);
cat = /[a-z]/;
var smalls = cat.test(str);
cat = /[A-Z]/;
var bigs = cat.test(str);
var corps = corpses(pwdinput);
var num = maths + smalls + bigs + corps;
if (len < 6) { return 1; }
if (len >= 6 && len <= 8) {
if (num == 1) return 1;
if (num == 2 || num == 3) return 2;
if (num == 4) return 3;
}
if (len > 8 && len <= 11) {
if (num == 1) return 2;
if (num == 2) return 3;
if (num == 3) return 4;
if (num == 4) return 5;
}
if (len > 11) {
if (num == 1) return 3;
if (num == 2) return 4;
if (num > 2) return 5;
}
}
function corpses(pwdinput) {
var cat = /./g
var str = $(pwdinput).val();
var sz = str.match(cat)
for (var i = 0; i < sz.length; i++) {
cat = /\d/;
maths_01 = cat.test(sz[i]);
cat = /[a-z]/;
smalls_01 = cat.test(sz[i]);
cat = /[A-Z]/;
bigs_01 = cat.test(sz[i]);
if (!maths_01 && !smalls_01 && !bigs_01) { return true; }
}
return false;
}
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